Python Pattern Program

PROJECT BY (SIMPLIFY LEARN PROGRAMMING)  ON K-SHAPE CHARACTER PATTERN   SOURCE CODE: for i in range(7):     for j in range(7):         if j == 0 or i - j == 3 or i + j == 3:             print("*", end="")         else:             print(end=" ")     print() OUTPUT:        

PROJECT BY (SIMPLIFY LEARN PROGRAMMING)  ON CHARACTER PATTERN   SOURCE CODE: def pattern(n):     k = 2 * n - 2     x = 65     for i in range(0, n):         for j in range(0, k):             print(end=" ")         k = k - 1         for j in range(0, i + 1):             ch = chr(x)             print(ch, end=" ")             x += 1         print("\r") pattern(7) OUTPUT:        

PROJECT BY (SIMPLIFY LEARN PROGRAMMING)  ON RIGHT ALPHABETICAL TRIANGLE CHARACTER PATTERN   SOURCE CODE: def pattern(n):     x = 65     for i in range(0, n):         ch = chr(x)         x += 1         for j in range(0, i + 1):             print(ch, end=" ")         print("\r")   pattern(5) OUTPUT:        

PROJECT BY (SIMPLIFY LEARN PROGRAMMING)  ON BINARY NUMBER PATTERN   SOURCE CODE: def pattern(n):     k = 2 * n - 2     for i in range(0, n):         for j in range(0, k):             print(end=" ")         k = k - 1         for j in range(0, i + 1):             print('10', end="")           print("\r")   pattern(5) OUTPUT:        

PROJECT BY (SIMPLIFY LEARN PROGRAMMING)  ON DESCENDING ORDER NUMBER PATTERN   SOURCE CODE: def pattern(n):     for i in range(n, 0, -1):         for j in range(1, i + 1):             print(j, end=" ")           print("\r")   pattern(5) OUTPUT:        

PROJECT BY (SIMPLIFY LEARN PROGRAMMING)  ON DIAMOND NUMBER PATTERN   SOURCE CODE: def pattern(n):     k = 2 * n - 2     x = 0     for i in range(0, n):         x += 1         for j in range(0, k):             print(end=" ")         k = k - 1         for j in range(0, i + 1):             print(x, end=" ")         print("\r")     k = n - 2     x = n + 2     for i in range(n, -1, -1):         x -= 1         for j in range(k, 0, -1):             p...